SQL 到聚合映射图表

在本页面

聚合管道允许 MongoDB 提供与 SQL 中许多 common 数据聚合操作相对应的本机聚合功能。

以下 table 概述了 common SQL 聚合术语,函数和概念以及相应的 MongoDB 聚合运算符

SQL 术语,函数和概念 Mongo聚合命令
WHERE $match
GROUP BY $group
HAVING $match
SELECT $project
ORDER BY $sort
LIMIT $limit
SUM() $sum
COUNT() $sum
$sortByCount
join $lookup
SELECT INTO NEW_TABLE $out
MERGE INTO TABLE $merge (从MongoDB 4.2开始可用)

有关所有聚合管道和表达式 operators 的列表,请参阅聚合管道快速参考

也可以看看

SQL 到 MongoDB 映射图表](SQL-to-Aggregation-Mapping-Chart.md)

例子

以下 table 提供了 SQL 聚合 statements 和相应的 MongoDB statements 的快速 reference。 table 中的示例假定以下条件:

  • SQL 示例假设两个表ordersorder_lineitemorder_lineitem.order_idorders.id列连接。

  • MongoDB 示例假设一个集合orders包含以下原型的文档:

    {
      cust_id: "abc123",
      ord_date: ISODate("2012-11-02T17:04:11.102Z"),
      status: 'A',
      price: 50,
      items: [ { sku: "xxx", qty: 25, price: 1 },
               { sku: "yyy", qty: 25, price: 1 } ]
    }
    
SQL语句 MongoDB语句 描述
SELECT COUNT(*) AS countFROM orders db.orders.aggregate( [ { $group: { _id: null, count: { $sum: 1 } } }] ) 计算来自orders的所有记录
SELECT SUM(price) AS totalFROM orders db.orders.aggregate( [ { $group: { _id: null, total: { $sum: "$price" } } }] ) orders中对price字段求和
SELECT cust_id, SUM(price) AS totalFROM ordersGROUP BY cust_id db.orders.aggregate( [ { $group: { _id: "$cust_id", total: { $sum: "$price" } } }] ) 对于每个唯一cust_id,对price字段进行求和。
SELECT cust_id, SUM(price) AS totalFROM ordersGROUP BY cust_idORDER BY total db.orders.aggregate( [ { $group: { _id: "$cust_id", total: { $sum: "$price" } } }, { $sort: { total: 1 } }] ) 对于每个唯一cust_id,求和price字段,结果按总和排序。
SELECT cust_id, ord_date, SUM(price) AS totalFROM ordersGROUP BY cust_id, ord_date db.orders.aggregate( [ { $group: { _id: { cust_id: "$cust_id", ord_date: { $dateToString: { format: "%Y-%m-%d", date: "$ord_date" }} }, total: { $sum: "$price" } } }] ) 对于每个唯一的cust_id,通过ord_date分组,将price字段相加。排除 data 的 time 部分。
SELECT cust_id, count(*)FROM ordersGROUP BY cust_idHAVING count(*) > 1 db.orders.aggregate( [ { $group: { _id: "$cust_id", count: { $sum: 1 } } }, { $match: { count: { $gt: 1 } } }] ) 对于具有多个记录的cust_id,返回cust_id和相应的 record 计数。
SELECT cust_id, ord_date, SUM(price) AS totalFROM ordersGROUP BY cust_id, ord_dateHAVING total > 250 db.orders.aggregate( [ { $group: { _id: { cust_id: "$cust_id", ord_date: { $dateToString: { format: "%Y-%m-%d", date: "$ord_date" }} }, total: { $sum: "$price" } } }, { $match: { total: { $gt: 250 } } }] ) 对于每个唯一的cust_id,通过ord_date分组,仅在总和大于 250 的情况下对price字段和 return 求和。排除 date 的 time 部分
SELECT cust_id, SUM(price) as totalFROM ordersWHERE status = 'A'GROUP BY cust_id db.orders.aggregate( [ { $match: { status: 'A' } }, { $group: { _id: "$cust_id", total: { $sum: "$price" } } }] ) 对于状态为A的每个唯一cust_id,请对price字段求和。
SELECT cust_id, SUM(price) as totalFROM ordersWHERE status = 'A'GROUP BY cust_idHAVING total > 250 db.orders.aggregate( [ { $match: { status: 'A' } }, { $group: { _id: "$cust_id", total: { $sum: "$price" } } }, { $match: { total: { $gt: 250 } } }] ) 对于状态为A的每个唯一cust_id,仅对总和大于 250 的price字段和 return 求和。
SELECT cust_id, SUM(li.qty) as qtyFROM orders o, order_lineitem liWHERE li.order_id = o.idGROUP BY cust_id db.orders.aggregate( [ { $unwind: "$items" }, { $group: { _id: "$cust_id", qty: { $sum: "$items.qty" } } }] ) 对于每个唯一cust_id,将与订单关联的相应 line item qty字段相加。
SELECT COUNT(*)FROM (SELECT cust_id, ord_date FROM orders GROUP BY cust_id, ord_date) as DerivedTable db.orders.aggregate( [ { $group: { _id: { cust_id: "$cust_id", ord_date: { $dateToString: { format: "%Y-%m-%d", date: "$ord_date" }} } } }, { $group: { _id: null, count: { $sum: 1 } } }] ) 计算不同的cust_idord_date分组的数量。排除 date 的 time 部分。

也可以看看

译者:李冠飞

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