在本页面
聚合管道允许 MongoDB 提供与 SQL 中许多 common 数据聚合操作相对应的本机聚合功能。
以下 table 概述了 common SQL 聚合术语,函数和概念以及相应的 MongoDB 聚合运算符:
SQL 术语,函数和概念 | Mongo聚合命令 |
---|---|
WHERE | $match |
GROUP BY | $group |
HAVING | $match |
SELECT | $project |
ORDER BY | $sort |
LIMIT | $limit |
SUM() | $sum |
COUNT() | $sum $sortByCount |
join | $lookup |
SELECT INTO NEW_TABLE | $out |
MERGE INTO TABLE | $merge (从MongoDB 4.2开始可用) |
有关所有聚合管道和表达式 operators 的列表,请参阅聚合管道快速参考。
也可以看看
SQL 到 MongoDB 映射图表](SQL-to-Aggregation-Mapping-Chart.md)
例子
以下 table 提供了 SQL 聚合 statements 和相应的 MongoDB statements 的快速 reference。 table 中的示例假定以下条件:
SQL 示例假设两个表
orders
和order_lineitem
由order_lineitem.order_id
和orders.id
列连接。MongoDB 示例假设一个集合
orders
包含以下原型的文档:{ cust_id: "abc123", ord_date: ISODate("2012-11-02T17:04:11.102Z"), status: 'A', price: 50, items: [ { sku: "xxx", qty: 25, price: 1 }, { sku: "yyy", qty: 25, price: 1 } ] }
SQL语句 | MongoDB语句 | 描述 |
---|---|---|
SELECT COUNT(*) AS countFROM orders |
db.orders.aggregate( [ { $group: { _id: null, count: { $sum: 1 } } }] ) |
计算来自orders 的所有记录 |
SELECT SUM(price) AS totalFROM orders |
db.orders.aggregate( [ { $group: { _id: null, total: { $sum: "$price" } } }] ) |
orders 中对price 字段求和 |
SELECT cust_id, SUM(price) AS totalFROM ordersGROUP BY cust_id |
db.orders.aggregate( [ { $group: { _id: "$cust_id", total: { $sum: "$price" } } }] ) |
对于每个唯一cust_id ,对price 字段进行求和。 |
SELECT cust_id, SUM(price) AS totalFROM ordersGROUP BY cust_idORDER BY total |
db.orders.aggregate( [ { $group: { _id: "$cust_id", total: { $sum: "$price" } } }, { $sort: { total: 1 } }] ) |
对于每个唯一cust_id ,求和price 字段,结果按总和排序。 |
SELECT cust_id, ord_date, SUM(price) AS totalFROM ordersGROUP BY cust_id, ord_date |
db.orders.aggregate( [ { $group: { _id: { cust_id: "$cust_id", ord_date: { $dateToString: { format: "%Y-%m-%d", date: "$ord_date" }} }, total: { $sum: "$price" } } }] ) |
对于每个唯一的cust_id ,通过ord_date 分组,将price 字段相加。排除 data 的 time 部分。 |
SELECT cust_id, count(*)FROM ordersGROUP BY cust_idHAVING count(*) > 1 |
db.orders.aggregate( [ { $group: { _id: "$cust_id", count: { $sum: 1 } } }, { $match: { count: { $gt: 1 } } }] ) |
对于具有多个记录的cust_id ,返回cust_id 和相应的 record 计数。 |
SELECT cust_id, ord_date, SUM(price) AS totalFROM ordersGROUP BY cust_id, ord_dateHAVING total > 250 |
db.orders.aggregate( [ { $group: { _id: { cust_id: "$cust_id", ord_date: { $dateToString: { format: "%Y-%m-%d", date: "$ord_date" }} }, total: { $sum: "$price" } } }, { $match: { total: { $gt: 250 } } }] ) |
对于每个唯一的cust_id ,通过ord_date 分组,仅在总和大于 250 的情况下对price 字段和 return 求和。排除 date 的 time 部分 |
SELECT cust_id, SUM(price) as totalFROM ordersWHERE status = 'A'GROUP BY cust_id |
db.orders.aggregate( [ { $match: { status: 'A' } }, { $group: { _id: "$cust_id", total: { $sum: "$price" } } }] ) |
对于状态为A 的每个唯一cust_id ,请对price 字段求和。 |
SELECT cust_id, SUM(price) as totalFROM ordersWHERE status = 'A'GROUP BY cust_idHAVING total > 250 |
db.orders.aggregate( [ { $match: { status: 'A' } }, { $group: { _id: "$cust_id", total: { $sum: "$price" } } }, { $match: { total: { $gt: 250 } } }] ) |
对于状态为A 的每个唯一cust_id ,仅对总和大于 250 的price 字段和 return 求和。 |
SELECT cust_id, SUM(li.qty) as qtyFROM orders o, order_lineitem liWHERE li.order_id = o.idGROUP BY cust_id |
db.orders.aggregate( [ { $unwind: "$items" }, { $group: { _id: "$cust_id", qty: { $sum: "$items.qty" } } }] ) |
对于每个唯一cust_id ,将与订单关联的相应 line item qty 字段相加。 |
SELECT COUNT(*)FROM (SELECT cust_id, ord_date FROM orders GROUP BY cust_id, ord_date) as DerivedTable |
db.orders.aggregate( [ { $group: { _id: { cust_id: "$cust_id", ord_date: { $dateToString: { format: "%Y-%m-%d", date: "$ord_date" }} } } }, { $group: { _id: null, count: { $sum: 1 } } }] ) |
计算不同的cust_id ,ord_date 分组的数量。排除 date 的 time 部分。 |
也可以看看
译者:李冠飞
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